72x^2-220x+168=0

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Solution for 72x^2-220x+168=0 equation:



72x^2-220x+168=0
a = 72; b = -220; c = +168;
Δ = b2-4ac
Δ = -2202-4·72·168
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-220)-4}{2*72}=\frac{216}{144} =1+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-220)+4}{2*72}=\frac{224}{144} =1+5/9 $

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